3m^2+m-56=-4

Solution for 3m^2+m-56=-4 equation:

3m^2+m-56=-4

We move all terms to the left:

3m^2+m-56-(-4)=0

We add all the numbers together, and all the variables

3m^2+m-52=0

a = 3; b = 1; c = -52;
Δ = b2-4ac
Δ = 12-4·3·(-52)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-25}{2*3}=\frac{-26}{6}
=-4+1/3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+25}{2*3}=\frac{24}{6}
=4
$